Two of us both had the Vintage Books edition, September 1980 printing of Gödel, Escher, Bach, a version that would have been available to solvers and was likely to be the one they used. We don't know if there are other editions with different pagination, but this one worked. All page number references below are to that edition.
UARYRAGRSMNAUASORWB YOU'VE SOLVED THE CODE. IS THIS THE END? THATS HOW IT MIGHT APPEAR, BUT ENDS AREN'T ALWAYS WHERE THEY SEEM, THE END IS NOT YET HERE, THE LAST SPEECH IN THE ARIA WITH DIVERSE VARIATIONS IS WHAT CONTAINS THE ANSWER THAT WILL END YOUR CEREBRATIONS, THE ANSWER IS THE TITLE TO A HIT BY AIR SUPPLY, SHOULD YOU NOT SEE IT, READ AGAIN AND GIVE IT ONE MORE TRY. EMSLSSSSALRGMRNGAECTSGSARRSDIThe beginning and end are junk, but the middle is an instruction referring to the Aria with Diverse Variations that appears beginning on page 391 of GEB. If you just jump to the end of the text on page 405, you will not find the answer. But if you actually read the Aria, you will see that on pages 402-403 the characters discuss the subject of making the reader have to search for the end of a text by putting some red herring content after the actual end. There are several clues, but most notably the missing letters in Tortoise's last speech on page 404 tell you that this speech is the actual end of the Aria, and the knock and the following part is not really part of the story. So the answer is found in that speech, and it is SWEET DREAMS.
Each legal move either adds chips into or removes chips from pile B or pile D. Treat each game as a 2-heap nim game with these heaps, ignoring the others. The game is called bogus because chips can sometimes be added to a pile instead of removed from it. But after the second player makes any such move, the first player can return to an equivalent state by removing those same chips; the first player never needs to do so. Because there is a finite supply of chips to the left of these piles, there is a finite number of moves which add chips available, and so it is effectively just regular nim.
Two-heap nim is easy: You just make the piles the same size. So you win by moving 2 chips out of D, 8 chips out of D, 6 chips out of D, 21 chips out of D, and 5 chips out of B. Concatenate these per the instructions, and write with a comma as suggested by the example, to get the answer 286,215.
Part of this puzzle is segment #3 of the audio tape, listed on the program as 8:10: Ornithography: Tweety Bird and Friends.
This puzzle is an audio cryptogram. Each bird call represents a different letter, and there are gaps between words. (There is an error in the audio: the gap between the first two words is missing). The page in the puzzle packet contains 20 clusters of bird footprints, and they correspond to words. Two bird feet = 1 bird call = 1 letter. So the lengths are 2, 5, 2, 3, 8, 3, 5, 4, 6, 3, 1, 6, 3, 1, 6, 3, 1, 6, 3, 4. The words start at approximately these offsets in the audio track: 0:00, 0:08, 0:28, 0:37, 0:51, 1:20, 1:34, 1:55, 2:11, 2:32, 2:46, 2:53, 3:15, 3:27, 3:33, 3:54, 4:06. (Another error in the puzzle: There are too many sets of bird prints on the printed page. The sequence 6, 3, 1 repeats one time too many.) The noice starting at 4:20 appears to separate he audio tracks
The cryptogram decodes to HE ROCKS IN THE TREETOPS ALL NIGHT LONG HOPPIN AND A BOPPIN AND A SINGIN HIS SONG. The answer is ROCKIN ROCKIN
Part of this puzzle is on the audio tape. It's segment #1 listed in the program as 8:00: Lifestyles of the Rich and Famous: The Millennium's Top Sixteen Symphonic Highlights. The handout tells us to list the composers in chronological order as to when the music was composed (with a note that two of the pieces are ambiguous, but to use the date of first performance of the second piece, the publication date of the third). Then extract these letters from the composers: 5 3 2 1 1 2 7 2 2 3 4 2 7 3 6 8. A solving team got the answer ENIGMA VARIATIONS. In the order they appear on the tape, the compositions are
I couldn't identify two of them. Per the hint sheet, one of them is Gluck, who lived in the 1700s and has to be between Vivaldi and Haydn. This gives us PACH(E)LBEL HA(N)DEL V(I)VALDI (G)LUCK (M)OZART H(A)YDN BEETHO(V)EN W(A)GNER B(R)AHMS SA(I)NT-SAENS TCH(A)IKOVSKY (Someone with 2nd letter T) GERSHW(I)N SH(O)STAKOVICH COPLA(N)D WILLIAM(S) to spell ENIGMA VARIATIONS.
........M. .U........ ......N... ...N...... .......... .......O..It's not particularly obvious from this, but the answer is UNMON, the name of a Zen Master who appears on page 254 of GEB. (The puzzle text says the answer will be a person's name.)
This puzzle is on the tape. It's segment #4, listed in the program as 8:14, Soundstage Presents Moxy Früvous. It's a complete recording of "The Drinking Song" by Moxy Fruvous, so it sounds similar to this. The lyrics match these to the word. There's also sheet music for it, matching the statement in the puzzle that the song is in G (because I have neither the musical ear nor the patience to transcribe all those notes). But following the directions to write down all "spellsung" words whose spelling matches at least one of the notes it's sung on (even if a different syllable is sung there), we get this list:
BAND PLAYED HELICOPTERS THE NUCLEAR A SOLID REMINDER SWEET AND SOME RECORDS BLACK STOOD BAND PLAYED HELICOPTERS THE NUCLEAR BETWEEN WE'RE LIKE CHAISE AROUND DOWN OPENED NOTICE DRINKING'S CAMPAIGN AND SCOTCHES BAND PLAYED HELICOPTERS THE NUCLEAR DISASTER WINDOW PLAYED NINTENDO GOOD NIGHT NIGHT GOOD IRENE IMPOTENT BONES EXTINCTION FLYING GRACEFUL BUT CANNOT BAND PLAYED HELICOPTERS THE NUCLEAR DECK MORNING GOODBYE HAMMERED SPUTTERED STAMMERED TOLD COULDN'T A ARMAGEDDON AMBULANCE FLYING DRANK AGAIN BAND PLAYED HELICOPTERS THE NUCLEAR
The sheet music also has the right lyrics. In compiling the list, I took "good night" to be two words (the linked lyrics site has it as one) and corrected the spelling of campaign in the sheet music (missing the G, which is the note it hit).
Now we have to delete any group of three words where the first is the same as the last (which is none of them, unless we take goodnight as a solid word, in which case all three goodnights are on the list and they get removed). Then for each repeated word, delete all occurrences except the first. That gets rid of the repettions of the chorus, A, PLAYED, GOOD, NIGHT, AND, and FLYING. We reverse RECORDS and AROUND. To make it work, I had to assume one other spellsung word from the chorus, and one before NOTICE, which I've marked as [missing]. I also had to assume that we do delete all the GOODNIGHTS. The final word list is:
BAND PLAYED HELICOPTERS THE NUCLEAR [missing] A SOLID REMINDER SWEET AND EMOS RECORDS BLACK STOOD BETWEEN WE'RE LIKE ESIAHC AROUND DOWN OPENED [missing] NOTICE DRINKING'S CAMPAIGN SCOTCHES DISASTER WINDOW NINTENDO IRENE IMPOTENT BONES EXTINCTION FLYING GRACEFUL BUT CANNOT DECK MORNING GOODBYE HAMMERED SPUTTERED STAMMERED TOLD COULDN'T ARMAGEDDON AMBULANCE DRANK AGAIN
Then we take the last letters of words 7, 15, 24, 33, 38, 48, which are A STOOD NOTICE BONES CANNOT AMBULANCE to give ADESTE, and the first letters of 35, 32, 25, 19, 18, 12, 8. These are FLYING IMPOTENT DRINKING'S ESIAHC LIKE EMOS SOLID to give FIDELES. The answer is ADESTE FIDELES.
Then match the numbers with pieces, rotating them so that the
intended numbers are upright. Each number appears on only one
piece and exactly one of the numbers appears on each piece. The
spaces between the pieces spell ESREVER, which is REVERSE
spelled backwards. For the second part of the answer, just plug
the numbers into the formula to get 723.
COMPLIMENTMONSTEROUSSURPRIZECAPITOLCONGRADULATIONSDISFUNCTIONALEMBARASSEDAFFECT
Now remove every other letter, starting with the first:OPIETOSEOSUPIEAIOCNRDLTOSIFNTOAEBRSEAFC
For every string of all consonants or all vowels of length greater than two, remove all but the first two:OPIETOSEOSUPIECNOSIFNOABREAFC
Replace both instances of PIE with CAKE:OCAKETOSEOSUCAKECNOSIFNOABREAFC
Remove all three instances of OS:OCAKETEUCAKECNIFNOABREAFC
Remove the reversed CUE:OCAKETAKECNIFNOABREAFC
Remove the conjunction IF:OCAKETAKECNNOABREAFC
Twenty letters remain. Take the last five, reverse them, and move them after the tenth letter:OCAKETAKECCFAERNNOAB
Change all Rs to Ls and all Ns to Ts:OCAKETAKECCFAELTTOAB
Remove TAKE:OCAKECCFAELTTOAB
The FA of "fad" appears in the string; replace it with the D:OCAKECCDELTTOAB
Remove CC:OCAKEDELTTOAB
Change the first A to an R, and remove the other A:OCRKEDELTTOB
And reverse the first two characters, along with the whole second half of the string:CORKEDBOTTLE
CORKED BOTTLE is the answer.
7523 ------ 27)260165 241 --- 171 163 --- 66 56 -- 105 105 --- 0Now the letters off to the side translate to 467, 103. This needs to be converted back to base 10 to get the correct answer, 311,67.
A right R up I left E up T right T right G down I left E left T up T right E down T left A down R right M right I down T left A left R downApplying the shifts as instructed yields DSITEPJBIVALVEXMBNET. The clear longest word is BIVALVE.
ABCDEFGHIJKLMNOPQRSTUVWXYZ QUARTZGLYPHJOBVEXDCWMFINKSUse this as a cipher key, decoding J, the number above 1 in the example, once by finding the letter below where J appears in the alphabet, which is P. Do the same for N, which appears above 2, but do it twice, decoding N to B and B to U. Continuing in this way yields PUZZLERS. Doing the same for the second set yields HAUSSMANN, the answer.
FROZ | ONOSCO | ELL |
PEA | OTO | PE |
PHON | OGR | OOD |
ELECT | TRICBAT | VENTION |
STROBEPH | ENF | ER |
COT | NUTBUTT | PHCODES |
SH | LEGRA | TER |
THREEP | TONG | NE |
IC | ARTIN | LLENSES |
TE | EPH | ONE |
BA | LYLI | TERY |
ASSEMB | LW | GRAPHY |
BIFO | CA | LU |
OI | RD | IN |
TEL | ROME | APH |
FROZEN FOOD | BIRDSEYE |
PEANUT BUTTER | CARVER |
PHONOGRAPH | EDISON |
ELECTRIC BATTERY | VOLTA |
STROBE PHOTOGRAPHY | EDGERTON |
COTTON GIN | WHITNEY |
SHRDLU | WINOGRAD |
THREE-PART INVENTION | BACH |
ICONOSCOPE | ZWORYKIN |
TELEGRAPH CODES | MORSE |
BAROMETER | TORRICELLI |
ASSEMBLY LINE | FORD |
BIFOCAL LENSES | FRANKLIN |
OIL WELL | DRAKE |
TELEPHONE | BELL |
Morse winOgrad Zworykin cArver fRanklin edgerTon birdSeye Ford edisOn dRake whiTney torrIcelli bEll volTa bacHMOZART'S FORTIETH is the answer.
DAVINCILAZFZETK TVXMKOLLWITZFML YZNMNRBMMESALTE MTVEMBYBAYRUAZE CALDERWBTYVWDIN XOKELLYNAFAHEAK NTDNARBRYDINEXY WHAZOLHAKEPIYRA KPKLLTIEPMINFVR EHLEZFTANSEYAFHThe highlighted letters above are the ones not in any such group. They spell CONSTRUCTION WORKERS.
White | from | to | Black | from | to |
---|---|---|---|---|---|
a4 | 7 | 5 | c6 | 18 | 19 |
a5 | 5 | 4 | Qb6 | 25 | 11 |
a5xQb6 | 4 | 11 | Kd8 | 33 | 25 |
b6xa7 | 11 | 2 | Kc7 | 25 | 18 |
a7xNb8=R | 2 | 9 | RxRa1 | 1 | 8 |
b | ɛ | s | t | d | ʌ | m | ʌ | p | s | |||||
æ | l | t | o | r | u | l | o | ʌ | g | ər | ʌ | |||
s | k | u | p | s | ɪ | r | o | d | t | o | l | d | ||
ɛ | k | s | h | ʌ | v | ər | ||||||||
m | ʌ | d | s | i | k | ɒ | m | i | k | l | aɪ | |||
u | d | o | ʌ | w | eɪ | ʌ | s | w | aɪ | d͡ʒ | ||||
s | u | n | ɒ | m | i | w | ɪ | n | d | |||||
eɪ | t | i | v | i | l | |||||||||
æ | k | t | ər | l | æ | p | t | ɒ | p | |||||
k | w | ɪ | z | d | w | aɪ | n | ɪ | n | ər | ||||
s | ɒ | d | ɔ | r | ʌ | i | z | D | h | ər | s | |||
f | r | i | d | k | ər | ʌ | ||||||||
d | o | m | ʌ | t | r | aɪ | l | l | ʌ | ʃ | l | i | ||
aɪ | k | ɒ | n | r | ɛ | d | i | p | r | u | v | |||
n | ʌ | b | aɪ | s | i | t | i | m | z |
Each of the zip codes leads to a university, but for some of them, the checksum is wrong. Those wrong checksums are struck out below:
For the second part of the answer, Oberlin, Haverford, and Kalamazoo were all founded in 1833. The youngest school is Hawaii Pacific which was founded in 1965, so was 31 years old at the time of the Hunt. The oldest school was Columbia, founded in 1754, 242 years old at the time of the Hunt. Dartmouth and Brown were also founded before 1800. Perform the calculations specified to get 476.
1 0 0-6 5 6-4 5 | | | | 1 2 2-1 3 3-4 2 3 0 3-1 4-5 6-6 | | 3 1 6 0-0 2-4 6 | | 2-2 5 5 6 2 4 1 | | | | 4 5-0 1 3 3 0 2 | | 4 3-0 5-5 4-1 6The letters corresponding to horizontal dominoes spell RIND ON THE WALL.
"I was talking the other day," said William Rogers to the other villagers gathered around the inn fire, "to a gentleman about the place called Louvain, what the Germans have burnt down. He said he knowed it well...used to visit a Belgian friend there. He said the house of his friend was in a long street, numbered on this side one, two, three, and so on, and that all the numbers on one side of him added up exactly the same as all the numbers on the other side of him. Funny thing that! He said he knew there was more than fifty houses on that side of the street, but not so many as five hundred. I made mention of the matter to our person, and he took a pencil and worked out the number of the house where the Belgian lived. I don't know how he done it." Perhaps the reader may like to discover the number of that house.The answer to this puzzle is simply the answer to the math problem (the one which fits between the limits of 50 and 500), which is 204.
TARARABOOMDEAY RDEFACERCOAXME IDOTIHDIORITES BEDELIABMNSONR ADARUNMIRYYOHO LTNMGEIGAMBLES MYGALSALDAEEXA ARETESOVERLIER MOTHERWASALADYThe songs are from the 1890s. The letters in the shaded squares spell the answer TRY TO REMEMBER. Clue answers:
Across: 1. song. 10. EYESIGHT - EIGHT. 11. RE(CAFE)D rev. 12. song. 13. dbl. def. 14. EDITOR IS anag. 16. song. 19. hidden: abroAD A Romantic. 20. RUIN MY anag. 22. HOY rev. + O. 26. BEG ALMS anag. 28. song. 29. hidden: tEXAn. 30. EASTER anag. 31. LOVER (L moved to end) + IE. 32. song. Down: 1. TRI(B)AL 2. DADDY -DY + ED? 3. HAMFATTER anag. 4. LIAR rev. 5. AS INCHES anag. 6. O + RIB + I. 7. M OR N (m and n are both abbreviations for noon, m from the Latin meridies). 8. song. 9. A + MEN. 12. song. 15. LOOT rev. 17. D + ANGORA - ORA. 18. song. 21. I'M rev. + A + OW. 23. HE(X)ED. 24. hidden: hasTY ROmeo. 25. hidden: bunGLE Every. 27. A RAM rev. 28. M + AM.
1 2@2 @ @ @ 4@6@4 @@@@@ 3@5@3After performing the indicated calculation and writing the result in base 36, the answer is 757MSSRS.
A[T]HENSGREECE BEET[H]OVEN CANDID[E] DU[M]ONT EINST[E]INONTHEBEACH [F]UTUREMAN GEO[R]GIA H-----[O]... INTHEHALLOFTHE[M]OUNTAINKING JEFFERSONAIRPLANE KRESGEAU[D]ITORIUM LAR[E]DO MUS[E]S NI[P]PER O[S]WALDTHELUCKYRABBIT [P]IERSON QUESER[A]SERA RODGERS SOUTHPACIFI[C] T... UNIT[E]DSTATES VA[N]COUVER WE[I]LL XA[N]ADUDIDKUBLAKHAN Y... ZIMBABW[E]Time has made some of the questions more difficult to research, but it's clear from what we have that the answer is THEME FROM DEEP SPACE NINE.
@@@..@.@...@.@.@...@..@@@. @..@.@.@@..@.@.@@..@.@...@ @..@.@.@.@.@.@.@.@.@.@.... @..@.@.@..@@.@.@..@@.@..@@ @..@.@.@...@.@.@...@.@...@ @..@.@.@...@.@.@...@.@...@ @@@..@.@...@.@.@...@..@@@.Forming the answer DINING.
These strings should all be considered together as an additional puzzle. The similarity of these strings across the different metas should clue solvers in to their relevance. Letter frequencies and some similarities in some of the strings (especially near the beginning and end of string 7, and between the last two strings) can help to determine the encoding used here.
Within each string, starting with the first letter, read every third letter, wrapping around until all letters are used, and then continue with the next string. With normal punctuation, spacing, and capitalization added, this reads:
Congratulations, you have discovered the impossible tribar.The first trail mentioned is clearly the last one in the packet, the Bach meta, based on a partial map of MIT. The answer it provides will be a room number, which works as an answer into the Gödel meta. (This was backsolved to be 6-207.) This is the second trail mentioned, which uses serial numbers from fire equipment around MIT. Based on a backsolve of the Escher meta, the word it gives is SYZYGY. The last trail is from the Escher meta. One of the instructions in that trail specifically sends you to the Boston Edison Company (a piece of equipment with their name on it) where we followed the extraction directions to get ODE TO JOY.The smallest room number in the 3rd passageway of one of the trails is one of the clues for one of the other trails.
On this latter trail you should take the 1st serial number, divide it by 49 and take the remainder. Do the same with the 2nd serial number except with 61 instead of 49. Do the same with the 3rd number except with 89, with the 4th number except with 53, with the 5th number except with 91, and with the 6th number except with 64. This will give you 6 numbers that you should convert to letters to spell out a clue for the remaining trail.
On this final trail obtain the clue for the 1st trail mentioned above by using the right hand column when you reach the Boston Edison Company. Take row 3 letter 5, row 1 letter 26, row 2 letter 3, row 4 letter 7, row 5 letter 8, row 7 letter 1, row 6 letter 13, and row 5 letter 2.
Puzzle | Answer | Starting point for key | Start of key text |
---|---|---|---|
1A | 29 | Beginning of page 29 | Three-Part Invention Achilles (a Greek warrior |
2B | 286,215 | Page 286, word 215 | left the game strategically almost the same |
3C | Unmon | Just after Unmon in the heading on page 254 | If words are bad and thinking is bad |
4C | reverse, 723 | The word reverse on page 723 | reverse order? A few words were changed |
5B | 4-405 | Page 4, word 405 | much, that he resolved to buy them all up. |
6A | 311, 67 | Page 311, word 67 | question is staring us all in the face |
7A | Haussmann | The name Haussmann in the photo credit on page 2 | Haussmann Introduction: A Musico-Logical Offering |
8B | 131, 112 | Page 131, word 112 | end in order to avoid the mental effort of keeping track |
9C | Hartley Rogers, 476 | The name Hartley Rogers on page 476 | Hartley Rogers' book, to explain. But the intuitive idea |
10C | 204 | Start of page 204 | CHAPTER VIII Typographical Number Theory The Crab Canon |
11B | 757MSSRS | The abbreviation Mssrs. on page 757 | Mssrs. C. H. O. Trevelyan from Sara Turing |
12A | 325, 413 | Page 325, word 413 | of all the neurons, and all the interconnections |
Tribar | 6-207 | Page 6, word 207 | carried out as well as possible, and it has |
The other clues tell us all the room numbers and the order to visit them. Two of these provide two separate clues which I have labeled a and b in the logic that follows.
Clues 3, 5a, 6, 7, and 11b give us several pairs of rooms that must be visited consecutively and in order: 321e-282, 034-001, 551-207, 365-044, 044-023. The last two pairs obviously combine into a single block of 3.
Clue 10 tells us 207 is exactly five checkpoints after 023, so this gives us the block 365-044-023-?-?-?-551-207.
Clue 4 tells us to visit three other rooms between 365 and 034, not necessarily in that order, which gives us one of the following two groupings: 034-001-?-?-365-044-023-?-?-?-551-207 or 365-044-023-?-034-001-551-207. The first of these is impossible because it is longer than 10 checkpoints.
We have the following additional clues which tell us to visit two rooms in a particular order, but not necessarily consecutively: Clue 5b: 562 before 282. Clue 11a: 001 before 321e. Clue 12: 562 before 551. Clue 11a forces the 321e-282 pair to come at the end of the sequence (immediately after 207, or else the sequence is too long). Then either of the other two clues is sufficient to place the remaining room (just by telling us that that room is 562, but for confirmation, both clues are correct) So the room sequence is 365-044-023-562-034-001-551-207-321e-282.
We attempted to perform this runaround. At 2-365 we found serial number 752512, which sends us to building 26. At 26-044, we found serial number 750996, which sends us to building 6. At 6-023, the closest serial numbers are 730506 and 730641, which would send us to buildings 6 and 5, respectively. The first two of these serial numbers match the first two letters of the backsolved answer SYZYGY which we got from the Escher meta, using the procedure described in the tribar solution. But neither of these serial numbers in building 6 works for the next letter (which should give us a serial number which is 26 modulo 89), so we think they are both wrong. There was a significant remodeling of building 6 which was completed in 2007, and we fear that this has caused the replacement or relocation of the fire equipment originally located near this room.
It may be possible to pick up the trail given that the next room number is 562, and most MIT buildings either do not have a 5th floor or do not have enough rooms on the fifth floor to number up to 562. It may even be possible then, given the third digit of the serial number, the last two digits each limited to 3 or 4 possibilities, that the number is six digits beginning with a 7 (at least, all the ones I have seen are), and that it must be 26 modulo 89, to backsolve the number that was supposed to be here (especially if it is a fire extinguisher and we know the fourth digit as well), or at least limit it to a handful of possibilities.
We now have the following solution for this puzzle from an archive document:
Room | Type | Serial Number |
---|---|---|
2-365 | hose | 752512 |
26-044 | hose | 750996 |
6-023 | hose | 752076 |
26-562 | ext. | 751088 |
16-034 | hose | 750484 |
4-001 | hose | 752089 |
E25-551 | ext. | 754797 |
E51-207 | hose | 753872 |
38-321E | hose | 751332 |
18-282 | hose | 750646 |
Plug the ten serial numbers into the formula given on the first page of this metapuzzle to get the final answer to this meta, 2545025.
Puzzle | Answer | Figure |
---|---|---|
1B | SHOEPRINT | 51 |
2A | LEAFYLAKE | 46 |
3A | POTSHERD | 71 |
4B | FLOATINGCASTLE | 12 |
5C | CORKEDBOTTLE | 24 |
6C | BIVALVE | ? |
7B | BANNER | 13 |
8A | CONSTRUCTIONWORKERS | 21 |
9A | CLOTHESPIN | ? |
10B | RINDONTHEWALL | 50 |
11C | ECHECS | 8 |
12C | DINING | 22 |
Tribar | SYZYGY | 48 |
Some comments:
We followed this runaround up to the Boston Edison Company, where we performed the letter extraction described in the Tribar, and then to step 32, which puts you into the alley between buildings 35 and 37.
But a newer archive document gives the final destination as the elevator in the lobby of E51, next to a sculpture by Frank Stella. We know from this article that two of his works were installed at MIT in 1995, Loohooloo and Heads or Tails. This page says Heads or Tails is installed in the E51 lobby (it also says it was acquired in 1997, in conflict wit the other article, but I'm ignoring that).
Whatever text we are extracting from in the last step gives the final answer to this runaround, FINGERYOYOATGAPPLECOM. We can reverse the code to get ?O?MO???GLCAPA?I?Y???????F??E?G???R?OP??????NT but except for the word CAPACITY it's not really enough to know what it says.
Puzzle | Answer |
---|---|
1C | Sweet Dreams (the puzzle confirms this is the song by Air Supply) |
2C | Rockin Robin |
3B | Enigma Variations |
4A | Adeste Fideles |
5A | And Can it be that I Should Gain |
6B | The Music of the Night |
7C | Mozart's Fortieth |
8C | Blue Suede Shoes |
9B | Honesty |
10A | Somewhere Over the Rainbow |
11A | Try to Remember |
12B | Theme from Deep Space Nine |
Tribar | Ode to Joy |
This meta was unsolvable, even during the Hunt in which it was run. There were attempted corrections given (which are not in the archives), but even then it had to be scrapped. We have noticed, for instance (even after considering that notes connected by a tie are treated musically as a single note), that staff 13 contains 15 notes, while it should only contain 14. (An errata list since obtained indeed noted there was an extra note in that staff, the fourth from the right.)
Even if we did manage to find all the correct songs, and the correct music for them, and resolve all the other errors, in order to find the runaround path, the solution then depends on the letters on the window panes in the doors along the path it describes. While many of these door inscriptions have been around for ages, they do sometimes change, and building 6 in particular was heavily remodeled several years ago. Even one changed door inscription could lead to wrong letters in the answer we get from this meta -- which the puzzle tells us will not be intelligible text, so we would never know.
Ultimately the answer had to be given to teams. This answer, per the instructions, is a string of gibberish letters that presumably the answers to the other two metas tell us how to decode. Mark Gottlieb describes the event in his 1998 thesis, Secrets of the MIT Mystery Hunt: An Exploration of the Theory Underlying the Construction of a Multi-Puzzle Contest:
The error in the 1996 Hunt was major and it was handled extremely well by the Puzzlemasters. This Hunt had three separate endgame puzzles; only one was broken. The team in the lead (Chaos; again, this was my team) had made great headway into the flawed puzzle; no other team was able to begin solving it. Chaos held approximately a five-hour lead over the second-place team based solely on the progress made on this endgame. This puzzle hadn't been test solved, so Chaos was actually the first group of people to attempt it. The puzzle was riddled with errors and subjective musical interpretations, so Chaos had worked closely with the PM's on this puzzle for a number of hours. (This collaboration allowed the PM's to correct their puzzle for other solvers and it allowed Chaos to make progress on it.) After a while, it became clear to both parties that this puzzle could not be successfully solved; meanwhile, the rest of the teams were complaining that they couldn't even begin to try. This endgame, the culmination of one-third of the contest, would have to be scrapped . . . the PM's released the answer to Chaos, waited thirty minutes to respect Chaos's lead, then gave everyone else the answer. Chaos went on to win the Mystery Hunt by that thirty-minute lead.
Despite this, tacotortoise on Livejournal (not to be confused with the Tortoise in this hunt) attempted to solve it anyway. He figured out Music of the Night and Adeste Fideles as two of the missing answers by examining the available notes. In the following images, each tune is marked with these abbreviations under each note:
Any note with a question mark is uncertain. Comments about these appear after each page. Some general comments from tacotortoise: "They seem to be inconsistent about whether accidentals carry through the line. If there is an accidental on a note, I would trust it, but be wary of other notes. Some of the durations in DS9 may be inaccurate; it has some irregular rhythms that are hard to transcribe. BSS and SD both get a little shaky around the third page; I don't trust their transcriptions (or lead sheets) at all. For BSS, they seem to be basing the melody off of Elvis Presley's version, but transposed from the key of Bb to the key of D. Or, again, their sheet music may have been a bit off."
A newer archive document (page 6 here) gives the note sequence as G F# F E E G F# G A E Eb D B C D D D C B A Bb A G F G B C B A Ab D G E C F E D C. (It has note lengths and indications of which notes are in a higher octave, but those aren't needed.)
Additionally, the tribar solution gives us a starting point, the 3rd segment of the path which goes by 6-207. Given that, we can trace out almost the whole path:
I couldn't place the last 4 notes. The A flat (note 30) has to be the one on the 3rd floor; out of the other A flats (stairwell in building 5 between 2nd and 3rd floors, building 2 1st floor, and building 7 basement) the first two do not have the required connections to both an A and a D, and the last does, but the A has no connection to a B.
But even so, we would be extracting a set of letters from the doors which are going to be impossible to confirm today, which we're told will be gibberish.
This erratum email (page
1) (2)
gives the complete sequence of doors to extract from, after the
deletions for the meta, and the letters extracted from them. We
don't know how many (if any) doors will match on each hallway, but
it mostly follows the path I marked above, except for some
discrepancies in building 2 (visiting the second floor and then
the basement before the first floor).
The solution to the Godel meta is a telephone number. At the time of the hunt, there was an answering machine message there which tells you to replace each number by the first letter of the corresponding word on page 302 of the book.
The solution to the Escher meta told us to finger
yoyo@atg.apple.com. This led to a plan file containing the
following numbers:
196 333 25 176 211 150 419 413 100 389 252 4 317 22 427 30 266 84
435 104 329 70 306 293 138 48 243 151 60 277 112 26 305 58 236 73
99 48 325 241 118 49 301 253 335 12 164 48 327 230 5 107 388 283
341 256 155 13 91 70 116 389 187 224 279 29 376 79 437 92 343 212
7 280
Using the method described on the answering machine, this decodes to copyafsmathlsaumichedugroupfactimhsujunkfootoathenaaddpgppgpfoo
Meaning to copy /afs/math.lsa.umich.edu/group/fac/timhsu/junk/foo to athena, then add pgp, then pgp foo.
The PGP passphrase to decode the file in the string of letters is obtained from the Bach meta. This requires actually following the meta path, which I couldn't finish, and which would probably not have all the same door numbers/letters as it did in 1996. But the newer archive solution file has this file, starting with "Hooray".
This file tells a story using the Tortoise and Achilles characters from GEB, providing a reason for them to have traveled to the Coney Island Ferris Wheel in the Little Harmonic Labyrinth story at page 103 of GEB, during which they get kidnapped. The story includes a poem about twirling an umbrella by moving some of its letters from one end to the other to make it a brellaum or laumbrel, and then it includes a uuencoded zip file.
I sent the image of uuencoded text through OCR with a lot of manual checking afterward, but I couldn't get a valid zip file out of it. Here's the uuencoded text I came up with.
You were supposed to figure out from the poem that the uuencoded text is broken and you need to fix it by replacing every U with M, M with B, and so on through UMBRELA, with A changing to U. That got me to this (mostly) corrected uuencode which gives a file fixed enough to unzip, but there are errors in two of the files which I was unable to find.
One file is a note from Achilles, which just comcludes the story and tells solvers the other files are the original ones that Hexachlorophene J. Goodfortune replaced with the ones to trap Achilles and the Tortoise during their own search for the coin. Each of these gives us yet another manipulation to apply to the metas.
To solve this puzzle, you must solve the ordering puzzle implicit in the Tortoise and Achilles dialogue in the Subjunc-TV Repair Manual (the puzzle packet) in the flavor text of the Godel puzzles.
1A This is where they started after drinking the pushing potion to get into the manual. They are starting to follow notes they made before taking it. They saw this part of the manual before pushing in.
2B They didn't see this part of the manual before pushing into it, but Achilles didn't realize until now there were such parts.
3C They haven't seen a single living thing since entering the manual. They just came from the cwm finks message.
4C They've done the minesweeper and now it's getting dark "again", and Tortoise is ready to go back (out of the manual). They have been through 27 sections of the manual.
5B It's Sunday. They haven't slept for 24 hours. This is "just about" the last section of the manual and Achilles says they can take a nap.
6A Achilles is ready for "another" snack.
7A They just woke up so late Saturday morning it's almost Saturday afternoon, after being up pretty late Friday night. This is the cwm finks puzzle.
8B They didn't see this part of the manual before. Achilles makes up a meaning for RICERCAR as an acronym involving chess, which is the puzzle here. And Achilles suggests taking a break to eat; the Tortoise brought plenty of food.
9C Achilles and the Tortoise are confused to encounter the versions of themselves who live in the repair manual. They just came from the cryptogram (clued in part by the Tortoise arriving ahead of our Achilles).
10C This is the cryptogram. With this stop they have visited every part of the manual they examined before drinking the potion. The Tortoise leaves this one before Achilles.
11B This is the minesweeper. The manual's versions of Achilles and the Tortoise are in the puzzle, and Achilles recognizes them and decides to stay away, unlike the other time they encountered them.
12A It's 6 AM Sunday. They drank the pushing potion on Friday.
There is flavor text in the non-Godel sections as well, but most of it doesn't give clues that helps place them, just hints for the puzzle they are on. But consider these:
So we can start by putting 1A first, and based on the things that come immediately after specific puzzles, put 7A immediately before 3C, 11B immediately before 4C, and 10C immediately before 9C. We also know 3C comes before they encounter their other selves in 9C, and 11B is after that. So we can order these sections: 1A ... 7A-3C ... 10C-9C ... 11B-4C.
There are several clues that give us some sort of time:
In 4C they say it's the 27th section, so they have 9 left. So this had to be before 5B ("just about the last"), so 4C is on Saturday evening. So 4C comes between 7A and 12A, and we have 1A ... 7A-3C ... 10C-9C ... 11B-4C ... 12A ... 5B.
In 11C they talk about it being too bad the Anteater couldn't stick around, and he was only there for an hour, so this must have been right after that. The Anteater was in 7C, a segment in which they had notes from before pushing in. So 7C had to be before 10C, where they say they've now visited all the sections of the manual they read before pushing in, and 11C, which they visited just afterward, is also before 10C. We've already established 10C is before 4C, which is on Saturday. Since they started Friday, 11C must be on Saturday, and 6A was on Friday, and before 7A, which was on Saturday.
They eat for the first time in the manual in 8B, and again in 6A, so 8B was before 6A
Section 2B is the first time Achilles sees a manual section that they didn't see before pushing in, and Tortoise says in that scene there were several of those. 8B is "another" such section, so it comes after 2B.
So now we can place the Godel sections in order:
1A 2B 8B 6A 7A 3C 10C 9C 11B 4C 12A 5B
And follow the instructions we were given:
If we were meant to use H, then the AP in the shifted sequence would have been SI. It doesn't affect either extraction.
For the last bit, we're supposed to pick 7 random points on a circle, draw all possible chords between pairs of the points (assuming no three chords intersect in the same point inside the circle), count the number of regions the interior of the circle is divided into (57; see below), and subtract 10 to get 47. So the answer to this part of the final meta is RO47
A convenient way to count the regions is to note that there are two at the edge between each pair of points, and three for each point facing inward. Now considering just the heptagon inside all those regions, there is one region at each vertex and one in the middle of each edge. Inside that is a 7-pointed star made of one region at each point, and a single heptagon in the center. So there are eight sets of seven, plus one, making 57.
Each Escher section of the manual has an answer that is an object that appears in one of Escher's works in the book. We have to find the page numbers, interpret each page number as a number in base 36, add these up, multiply by K (we are still working in base 36, so this is 20), and then add 400 Memorial Drive.
Funny thing, at the time I wrote the table for the Escher meta, I didn't have this text, but now I can complete the table and add page numbers. Clothespins appear at the lower right of Waterfall, where a woman is hanging clothes on a line.
The bivalve (a shellfish like a clam, oyster, or mussel with a two-part shell) was difficult to find. Mosaic II on page 61 has a bunch of animal shapes but not a bivalve. Castrovalva on page 550 has a snail in the detail at bottom left, but that's not a bivalve. There are also pictures with crabs and ants, not bivalves. There are two Escher pieces that undeniably contain bivalves, Shells and Starfish from 1941 and Sea Shells from 1949, which has scallop shells, but they aren't in the book. I ultimately decided it had to be the shape on the floor (ceiling?) in rthe middle of Convex and Concave on page 107, which I had taken to be an architectural element and not an actual shell.
It only counts manual sections, so we exclude the answer from the tribar.
Puzzle | Answer | Figure | Page |
---|---|---|---|
1B | SHOEPRINT | 51 | 256 |
2A | LEAFYLAKE | 46 | 247 |
3A | POTSHERD | 71 | 399 |
4B | FLOATINGCASTLE | 12 | 42 |
5C | CORKEDBOTTLE | 24 | 117 |
6C | BIVALVE | 23 | 107 |
7B | BANNER | 13 | 57 |
8A | CONSTRUCTIONWORKERS | 21 | 89 |
9A | CLOTHESPIN | 5 | 11 |
10B | RINDONTHEWALL | 50 | 253 |
11C | ECHECS | 8 | 14 |
12C | DINING | 22 | 98 |
Tribar | SYZYGY | 48 | 250 (excluded) |
So we do the base 36 math, getting 12-17-34 or 16198 in decimal. Multiply by 20 to get 323960. This is 6XYW in base 36. Now are we adding 400 Memorial Drive with the 400 is base 36? That is what the document appears to say. That would make 71YW.
If we are including SYZYGY on page 250, we get 84QW, 88QW after adding 400 in base 36. None of these make any sense. There is nothing with an address of 71, 84, or 88 on Memorial Drive.
So the bivalve is probably elsewhere.
The errata emails come to our aid now. we have to add up all the room numbers of the doors used to produce the PGP code, including the building numbers but excluding any letters in the room numbers. Those are 8-102 8-114 6-207 6-215 6-216 6-218 6-218 6-218 2-221 2-034 2-038 2-040 2-048 2-051 2-052 2-108 4-131 4-133 4-134 4-138 4-140 4-141 4-142 4-144 4-204 4-205 4-208 4-212 10-322 10-390 10-100 3-103 3-107 3-108 3-140 3-164 3-166 1-304 1-307 1-163 1-165 1-170 1-181. I assume it's meant to concatenate the digits and treat these are 4 or 5 digit numbers. This gives us 176922 as the value of x.
The next part says to take the three-letter word in large letters in Lobby 7 high above the entrance to the infinite corridor. The inscription is Established for Advancement and Development of Science its Application to Industry the Arts Agriculture and Commerce. Charter MDCCCLXI. And this photo shows us the the 3-letter word we want is FOR (only the side of Lobby 7 going into the Infinite Corridor has the blue-green doorways seen at the lower right).
We're supposed to shift the first letter forward by the sum of the first and fifth digits of x. Those are 1 and 2 so we shift 3 to I. Shift the second letter backwards by the sum of the digits of the of the room number of the Department of Alchemy, including the building number. It's easy to find this is 2-214 so we shift by 9. Then further shift backward by the last digit of x, which is 2. We end up with D We don't change the third letter. So IDR is the first part of the answer to this puzzle. The second part is the remainder when x/2 is divided by 4423, which is 1.
We ended up with RO47, 71YW Memorial Drive, IDR1. None of those answers make a lot of sense. The coin map tells us the final clue was FIRE DOOR 4-369, which doesn't look like anything we got.